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No, your Mac doesn't have I2C support. It was pointed out in the comments that there might be some legacy port, but it won't be usable due to driver limitations.

No, your Mac doesn't have I2C support. It was pointed out in the comments that there might be some legacy port, but it won't be usable due to driver limitations.

As far as debugging, there's a few options. First of all, there are a few ways to debug I2C using an oscilloscope. If that's too expensive, you could also get away with a logic analyzer. The one I just linked was at Sparkfun for $150. If that's still too expensive and you're willing to risk $30, you can find cheap ones on eBay (most with little/no documenation).

As far as debugging, there's a few options. First of all, there are a few ways to debug I2C using an oscilloscope. If that's too expensive, you could also get away with a logic analyzer. The one I just linked was at Sparkfun for $150. If that's still too expensive and you're willing to risk $30, you can find cheap ones on eBay (most with little/no documenation).

Edit: this seems like the Arduino code you want:

#include <Wire.h>

#define SLAVE_ADDRESS 0x04
int number = 0;
int num1 = 0;
int num2 = 0;
int state = 0;
boolean secondByte = false;

void setup() {
    pinMode(13, OUTPUT);
    Serial.begin(9600);         // start serial for output
    // initialize i2c as slave
    Wire.begin(SLAVE_ADDRESS);

    // define callbacks for i2c communication
    Wire.onReceive(receiveData);
    Wire.onRequest(sendData);

    Serial.println("Ready!");
}

void loop() {
    delay(100);
}

// callback for received data
void receiveData(int byteCount){
    while(Wire.available()) {
        if(secondByte) {
            num2 = Wire.read();
            number = (num1 << 8) + num2;

            Serial.print("data received: ");
            Serial.println(number);
            
            if (number == 1){
                if (state == 0){
                    digitalWrite(13, HIGH); // set the LED on
                    state = 1;
                }
                else{
                    digitalWrite(13, LOW); // set the LED off
                    state = 0;
                }
             }
         } else {
             num1 = Wire.read();
         }
         secondByte != secondByte;
    }
}

// callback for sending data
void sendData(){
    Wire.write(num1);
    Wire.write(num2);
}

The Python code will have to do the similar thing. Note: the first part of the number (reading left to right) will be sent first.