Revisions to How do I print multiple variables in a string?

The proposed code increases code size which is not desirable

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edited Dec 19, 2020 at 5:30

MatsK

1.4k
1
11
25

One possible solution is:

`Serial.println((String)"Var 1:" + var1 + " Var 2:" + var2 + " Var 3:"Serial.println((String)"Var 1:" + var1 + " Var 2:" + var2 + " Var 3:" + var3);

var3);`

The above solution from Iain increases code size.

One possible solution is:

`Serial.println((String)"Var 1:" + var1 + " Var 2:" + var2 + " Var 3:"

var3);`

The above solution from Iain increases code size.

One possible solution is:

Serial.println((String)"Var 1:" + var1 + " Var 2:" + var2 + " Var 3:" + var3);

The above solution from Iain increases code size.

The proposed code increases code size which is not desirable

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edit approved Dec 19, 2020 at 5:30

user31092

3
3

One possible solution is:

One possible solution is:

`Serial.println((String)"Var 1:" + var1 + " Var 2:" + var2 + " Var 3:"

var3);`

Serial.println((String)"Var 1:" + var1 + " Var 2:" + var2 + " Var 3:" + var3); The above solution from Iain increases code size.

One possible solution is:

Serial.println((String)"Var 1:" + var1 + " Var 2:" + var2 + " Var 3:" + var3);

One possible solution is:

`Serial.println((String)"Var 1:" + var1 + " Var 2:" + var2 + " Var 3:"

var3);`

The above solution from Iain increases code size.

proper code format and more verbose answer

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edit approved Oct 27, 2019 at 21:52

MichaelT

887
3
8
22

Serial.println((String)"Var 1:" + var1 + " Var 2:" + var2 + " Var 3One possible solution is:" + var3);

Serial.println((String)"Var 1:" + var1 + " Var 2:" + var2 + " Var 3:" + var3);

Serial.println((String)"Var 1:" + var1 + " Var 2:" + var2 + " Var 3:" + var3);

One possible solution is:

Serial.println((String)"Var 1:" + var1 + " Var 2:" + var2 + " Var 3:" + var3);

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answered Oct 25, 2019 at 4:24

Iain Crawford

31
1

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