You can copy the array:

EXCLUSIVE_COLOR[0] = colors[0][0];
EXCLUSIVE_COLOR[1] = colors[0][1];
EXCLUSIVE_COLOR[2] = colors[0][2];

but this doesn't work in an initialization.

Alternatively, you can declare EXCLUSIVE_COLOR as a pointer to an array of 3 integers:

int (*EXCLUSIVE_COLOR)[3]; // pointer to array 3 of int

Then you can have this point to a row of the 2D array, either by assigning the pointer or in the initialization:

int (*EXCLUSIVE_COLOR)[3] = &colors[0];  // initialization

// Later in the program:
EXCLUSIVE_COLOR = &colors[1];

Note that when using this pointer, you will have to explicitly dereference it:

for (int i = 0; i < 3; i++)
    Serial.println((*EXCLUSIVE_COLOR)[i]);

You can copy the array:

EXCLUSIVE_COLOR[0] = colors[0][0];
EXCLUSIVE_COLOR[1] = colors[0][1];
EXCLUSIVE_COLOR[2] = colors[0][2];

but this doesn't work in an initialization.

Alternatively, you can declare EXCLUSIVE_COLOR as a pointer to an array of 3 integers:

int (*EXCLUSIVE_COLOR)[3]; // pointer to array 3 of int

Then you can have this point to a row of the 2D array, either by assigning the pointer or in the initialization:

int (*EXCLUSIVE_COLOR)[3] = &colors[0];  // initialization

// Later in the program:
EXCLUSIVE_COLOR = &colors[1];

Note that when using this pointer, you will have to explicitly dereference it:

for (int i = 0; i < 3; i++)
    Serial.println((*EXCLUSIVE_COLOR)[i]);

Edit: As pointed out by Juraj in a comment, you can instead make EXCLUSIVE_COLOR a pointer to int. In this case you will make it point to the first element in the row you want:

int* EXCLUSIVE_COLOR = &colors[0][0];

One nice thing of this approach is that you can use the “decay to pointer” feature of the language to simplify the syntax:

int* EXCLUSIVE_COLOR = colors[0];

// Later
Serial.println(EXCLUSIVE_COLOR[i]);