Timeline for Powering USB device from arduino uno?
Current License: CC BY-SA 3.0
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| Mar 11, 2015 at 17:41 | comment | added | MattEE | As far as current limits I believe they are 500 mA for the 5V pin and 50 mA on each of the signal output pins. In regards to your original question, have you tried connecting ~9V DC to the Vin pin and testing for 5V on the USB port? I still believe this is your best option if it works. | |
| Mar 11, 2015 at 17:37 | comment | added | MattEE | The Vin pin is the input for external DC voltage, whereas the 5V pin is regulated as a 5V output for powering other equipment. For this reason using the Vin pin is safer because it regulates the outputs (including the 5V pin) to a constant 5V. If say 6 or 7 volts were applied to the 5V pin, you may damage the Arduino or draw unnecessary current from your power supply. I suggested 7-12V on Vin because this is the safe range specified by Arduino and will turn on the onboard voltage regulator. Turn the current to a max on the power supply, the actual current drawn is regulated by the Arduino | |
| Mar 11, 2015 at 16:44 | comment | added | Mouse'nKeyboard | Please correct me if I'm wrong: The vin pin gets its power from the external DC jack at whatever voltage is supplied, and so can the 5V (limiting voltage to 5) and they both share the available current from the DC input? Could you explain why using the vin pin is safer? Wouldn't it be fine to use the 5V since I am powering a USB 5V device? Also, I assume grounding a circuit on the arduino using a custom volt and/or amps DC power source may well damage the board? You stated max of 7-12Vs, any idea of what sort of max amps? | |
| Mar 11, 2015 at 13:52 | review | First posts | |||
| Mar 12, 2015 at 1:05 | |||||
| Mar 11, 2015 at 13:48 | history | answered | MattEE | CC BY-SA 3.0 |