Timeline for How to calculate phase shift between two square waveforms with Arduino DUE
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 4, 2015 at 10:07 | history | tweeted | twitter.com/#!/StackArduino/status/628507510643781634 | ||
| Mar 30, 2015 at 22:08 | history | migrated | from electronics.stackexchange.com (revisions) | ||
| Mar 24, 2015 at 20:04 | answer | added | hobbs | timeline score: 3 | |
| Mar 24, 2015 at 16:21 | answer | added | Karl Bielefeldt | timeline score: 3 | |
| Mar 24, 2015 at 16:05 | comment | added | Alex | The best solution would be to just capture time in ISR1 and ISR2. And then subtract the values and display the difference in the main loop at a slower speed. Obviously you may miss a few samples every now and then. | |
| Mar 24, 2015 at 16:01 | comment | added | Alex | @KyranF. I understand the asynch part but it still takes 1ms per byte. The only thing that can help here is buffering (FIFO) but eventually you will run out of buffer space anyway. | |
| Mar 24, 2015 at 15:59 | answer | added | Majenko | timeline score: 4 | |
| Mar 24, 2015 at 15:58 | comment | added | KyranF | chaya your output doesn't match the strings shown in the code, where are the lines showing "period" and "phase shift"? | |
| Mar 24, 2015 at 15:56 | comment | added | KyranF | chaya have you looked at an oscilloscope and seen if the numbers are correct, or even close at all? | |
| Mar 24, 2015 at 15:55 | comment | added | KyranF | @Alex the Due might have hardware serial, which is dealt with asynchronously by the hardware UART/USB. The Due is a powerful Cortex M3 I doubt there is any processing issue there.. | |
| Mar 24, 2015 at 15:52 | comment | added | Alex | First make sure you limit the data sent to the serial port inside your ISR when the interrupts are disabled. At 9600 baud it takes 1ms to send one byte over the serial link. | |
| Mar 24, 2015 at 15:40 | history | asked | chaya | CC BY-SA 3.0 |