std::mismatch
| Defined in header <algorithm>
|
||
| template< class InputIterator1, class InputIterator2 > std::pair<InputIterator1,InputIterator2> |
(1) | |
| template< class InputIterator1, class InputIterator2, class BinaryPredicate > std::pair<InputIterator1,InputIterator2> |
(2) | |
Returns the first mismatching pair of elements from two ranges: one defined by [first1, last1) and another starting at first2. The first version of the function uses operator== to compare the elements, the second version uses the given binary predicate p.
目次 |
Parameters
| first1, last1 | - | the first range of the elements |
| first2 | - | the beginning of the second range of the elements |
| p | - | if the elements should be treated as equal true を返す二項述語。 述語関数のシグネチャは以下と同等なものであるべきです。 bool pred(const Type1 &a, const Type2 &b); シグネチャが const & を持つ必要はありませんが、関数は渡されたオブジェクトを変更してはなならず、値カテゴリに関わらず |
Return value
std::pair with iterators to the first two non-equivalent elements, or, if no different elements found, pair with last1 and the corresponding iterator from the second range.
Complexity
At most last1 - first1 applications of the predicate
Possible implementation
| First version |
|---|
template<class InputIterator1, class InputIterator2> std::pair<InputIterator1, InputIterator2> mismatch(InputIterator1 first1, InputIterator1 last1, InputIterator2 first2) { for (; first1 != last1; ++first1, ++first2) { if (*first1 != *first2) { return std::make_pair(first1, first2); } } return std::make_pair(first1, first2); } |
| Second version |
template<class InputIterator1, class InputIterator2, class BinaryPredicate> std::pair<InputIterator1, InputIterator2> mismatch(InputIterator1 first1, InputIterator1 last1, InputIterator2 first2, BinaryPredicate p) { for (; first1 != last1; ++first1, ++first2) { if (!p(*first1, *first2)) { return std::make_pair(first1, first2); } } return std::make_pair(first1, first2); } |
Example
This program determines the the longest substring that is simultaneously found at the very beginning of the given string and at the very end of it, in reverse order (possibly overlapping)
#include <iostream> #include <string> #include <algorithm> std::string mirror_ends(const std::string& in) { return std::string(in.begin(), std::mismatch(in.begin(), in.end(), in.rbegin()).first); } int main() { std::cout << mirror_ends("abXYZba") << '\n' << mirror_ends("abca") << '\n' << mirror_ends("aba") << '\n'; }
出力:
ab a aba
