Revisions to How can I access the index value in a 'for' loop?

PEP 8. Internal formatting (only one backtick is necessary for inline).

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edited Apr 8, 2025 at 19:54

You can use enumerate and embed expressions inside string literals to obtain the solution.

This is a simple way:

a=[4a = [4, 5, 6, 8]
for b, val in enumerate(a):
    print('item #{} = {}'.format(b+1, val))

You can use enumerate and embed expressions inside string literals to obtain the solution.

This is a simple way:

a=[4,5,6,8]
for b, val in enumerate(a):
    print('item #{} = {}'.format(b+1, val))

You can use enumerate and embed expressions inside string literals to obtain the solution.

This is a simple way:

a = [4, 5, 6, 8]
for b, val in enumerate(a):
    print('item #{} = {}'.format(b+1, val))

formatting changes

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Lars

You can use enumerateenumerate and embed expressions inside string literals to obtain the solution.

This is a simple way:

a=[4,5,6,8]
for b, val in enumerate(a):
    print('item #{} = {}'.format(b+1, val))

You can use enumerate and embed expressions inside string literals to obtain the solution. This is a simple way

a=[4,5,6,8]
for b, val in enumerate(a):
print('item #{} = {}'.format(b+1, val))

You can use enumerate and embed expressions inside string literals to obtain the solution.

This is a simple way:

a=[4,5,6,8]
for b, val in enumerate(a):
    print('item #{} = {}'.format(b+1, val))

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answered Dec 18, 2021 at 16:05

Kofi

You can use enumerate and embed expressions inside string literals to obtain the solution. This is a simple way

a=[4,5,6,8]
for b, val in enumerate(a):
print('item #{} = {}'.format(b+1, val))

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