How can you create a 2D array,say, arr[][] with 5 rows and each row has a variable number of columns in it?
possibly arr[5][]
with 1st row arr[0][] with 4 columns
2nd row arr[1][] with 5 columns and so on?
I wouldn't mind a STL vector solution but I don't know vectors very well yet.
With C++11, you can do it easily with vectors (line breakes added for readability):
std::vector< std::vector <int > > arr = {
{1,2,3},
{4,5},
{6,7,8,9,0}
};
If you don't have a C++11 compiler, it works the exact same way, but you will not be able to initialize them as easy. You can set elements individually:
std::vector< std::vector <int > > arr;//vector of vectors. Think of each element as of a "row"
std::vector<int> sub;//a temporary "row"
sub.push_back(1);
sub.push_back(2);
arr.push_back(sub);//Adding a "row" to the vector
sub.clear();//Making another one
sub.push_back(1);
sub.push_back(12);
sub.push_back(54);
arr.push_back(sub);//Adding another "row" to the vector
Or you can initialize each "row" with an ordinary array:
std::vector< std::vector <int > > arr;
static const int arr[] = {1,2,3,4};//A "row" as an ordinary array
vector<int> vec (arr, arr + sizeof(arr) / sizeof(arr[0]) ); //Setting a "Row" as a vector
arr.push_back(vec);//Adding the "row" to the vector of vectors.
It's not exactly possible to do what you want with ordinary arrays, since when you make an array[X][Y], it automaticaly is an X*Y matrix. You could, however, use an array of pointers:
int * array[3];
//also possible: int ** array = new int*[3]; but don't forget to delete it afterwards.
int sub1[3] = {1,2,3};
int sub2[2] = {1,2};
int sub3[4] = {1,2,3,4};
array[0] = sub1;
array[1] = sub2;
array[2] = sub3;
and access elements with array[X][Y]. However, the vector solution is much better overall.
This International Standard specifies requirements for implementations of the C++ programming language. The first such requirement is that they implement the language, and so this International Standard also defines C++. However, I would really not like to argue about it. I tried to provide a full answer, though it took some time and a couple of edits. Sometimes it happens that one doesn't consider some things right away, and has to edit an answer later to include additional info.
Commented
Jul 18, 2012 at 6:49
You can do it like this (assuming an array of int elements):
int** arr = new int*[5];
for(size_t i = 0; i < 5; ++i)
{
arr[i] = new int[4];
}
and this gives you a two-dimensional dynamically allocated array of 5 by 4. You can then use it like this: arr[i][j] = 15;
Do not forget to de-allocate the memory after you are done using the array:
for(size_t i = 0; i < 5; ++i)
{
delete[] arr[i];
}
delete[] arr;
I would recommend using std::vector, however. You can see the other answers for reference.
A way for different row size
#include <iostream>
#include <string>
int main()
{
int test1[]={1,2,3};
int test2[]={4,5};
int *test[]={test1,test2};
std::cout << test[0][1];//2
std::cout << test[1][1];//5
}
So, 2D arrays is std::vector<std::vector<T>>, where T is type. Also, mb std::array<std::vector<int>, 5>. Or write your own array class.
