Python list to string

Question

Element3 of each list is a list (in brackets). I want element3 to be a string 'store1.txt' not ['store1.txt'].

store_list = [["Freds", "store1"], ["Sams", "store2"], ["Johns", "store3"], ["Toms", "store4"]]
urls_list = ['store1.txt', 'store2.txt', 'store3.txt', 'store4.txt', 'store5.txt', 'store6.txt']
ls = []
for x in store_list:
    str_num = x[1]
    matching = [s for s in urls_list if str_num in s]
    x.insert(3, matching)
    ls.append(x)
for i in ls:
    print i

Both ettanany and rassar's answers work on my example, but they do not work for my actual script. When adding the [0] to the end of the matching line I get an IndexError: list index out of range. When adding the .pop() I get and IndexError: pop from empty list. Sigh, but when I run the code without either, it does as it should and returns a list in that element. — precastnick, Commented Dec 8, 2016 at 21:29
I understand now. Some of the lists are empty because they were generated improperly, therefore an empty list cannot be popped. Thanks again for the awesomeness. — precastnick, Commented Dec 8, 2016 at 21:35

rassar · Accepted Answer · 2016-12-08 21:11:43Z

1

Change the 6th line to:

matching = [s for s in urls_list if str_num in s][0]

The list comprehension automatically generates a list, so you need to take the first value of that list if you just want the string.

answered Dec 8, 2016 at 21:11

rassar

5,6903 gold badges28 silver badges45 bronze badges

Wonderful rassar. Thank you.
– precastnick
Commented Dec 8, 2016 at 21:16

Add a comment |

ettanany · Accepted Answer · 2016-12-08 21:13:03Z

0

matching is a list, you can use pop() to get your element like this:

x.insert(3, matching.pop())

answered Dec 8, 2016 at 21:13

ettanany

19.9k9 gold badges49 silver badges63 bronze badges

Add a comment |

Collectives™ on Stack Overflow

Python list to string

2 Answers 2

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Related