Your error is here:
if [ DIR eq $1 ]
You are not using the variable, that's the simple string DIR. What you want is:
if [ "$DIR" = "$1" ]
However, since you are setting DIR="$1", that test will always be true by definition. Also, when $1 is empty, so will $DIR and the find command will be run on the current directory. For many versions of find, these commands are equivalent:
find . -name foo
find -name foo
In the absence of a target directory, find will search through ., the current directory. So, a working version of your script would be:
#!/bin/bash
## Avoid using UPPER CASE variable names in bash.
dir="$1"
## Check if $dir exists
if [ -e "$dir" ]
then
printf "total directories: %s\n" $(find "$dir" -type d | wc -l)
printf "total files: %s\n" $(find "$dir" -type f | wc -l)
else
echo " pass parameters"
fi
The number of arguments passed to a bash script is saved as $#, so you could also do
if [ $# -lt 1 ]
then
echo "pass parameters"
exit
fi