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edited Jun 21, 2012 at 23:34

Bash script variable Variable substitution with an exclamation mark in bash

I have the following lines in my .cfg bash script file

DDF_SOURCE="siebel_DATA_DATE_FORMAT"
DATA_DATE_FORMAT=${!DDF_SOURCE}

how is ${!DDF_SOURCE} evaluated? It would be !siebel_DATA_DATE_FORMAT, which doesn't make sense to me.

Thanks

Bash script variable

I have the following lines in my .cfg bash script file

DDF_SOURCE="siebel_DATA_DATE_FORMAT"
DATA_DATE_FORMAT=${!DDF_SOURCE}

how is ${!DDF_SOURCE} evaluated? It would be !siebel_DATA_DATE_FORMAT, which doesn't make sense to me.

Thanks

I have the following lines in my .cfg bash script file

DDF_SOURCE="siebel_DATA_DATE_FORMAT"
DATA_DATE_FORMAT=${!DDF_SOURCE}

how is ${!DDF_SOURCE} evaluated? It would be !siebel_DATA_DATE_FORMAT, which doesn't make sense to me.

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occurred Jun 21, 2012 at 19:34

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asked Jun 21, 2012 at 16:10

van

I have the following lines in my .cfg bash script file

DDF_SOURCE="siebel_DATA_DATE_FORMAT"
DATA_DATE_FORMAT=${!DDF_SOURCE}

how is ${!DDF_SOURCE} evaluated? It would be !siebel_DATA_DATE_FORMAT, which doesn't make sense to me.

Thanks

linux bash