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The appropriate answer is @laktak. But here there's another approach:
for f in *.gz;"$sourceFolder"; do echo "$" printing the file name ${f##*/}"; " done
for f in *.gz; do echo "${f##*/}"; done
for f in "$sourceFolder"; do echo " printing the file name ${f##*/}" done
The appropiateappropriate answer is @laktak (using the extension *.gz). But here there's another approach:
*.gz
for f in *.gz; do echo "${f##f##*/*}"; done
The appropiate answer is @laktak (using the extension *.gz). But here there's another approach:
for f in *.gz; do echo "${f##/*}"; done
