All Questions
8 questions
0
votes
2
answers
257
views
How to expand variable within a single-quoted argument?
I am trying to perform the following without luck:
SORT_BY='-k3,3r -k2,2 -k1,1r'
awk 'NR<4{print $0;next}{print $0 | sort '"${SORT_BY}"' -t"~"}'
I have tried with all sorts of quotes, unquote, etc....
- 285
0
votes
2
answers
5k
views
using awk to print backslash
I am having trouble printing (or searching) for sequences containing backslashes when using awk
For example -
echo "test\test" | awk '{ gsub(/\\\\t/, "\\\\&"); print }'
will give the result:
...
- 1
4
votes
1
answer
817
views
Prevent awk from removing "\" (backslashes) in variable
I have this line of code for the shell:
ls -1 *.mp3| awk -v here="$(cygpath -w $PWD)" -v source="$source" '{print "File Name: "$0"\n"here"\n"source}'
Unfortunately it outputs:
File Name: Data 00053....
- 259
1
vote
3
answers
6k
views
echo $ along with variable
Im trying to do print last directory like below
#!/bin/bash
dirc="/a/b/"
i=3
`echo "$dirc" | awk -F / '{ print ""$"i"}'`
which should print 'b', which is not happening.
- 189
0
votes
1
answer
3k
views
Escaping backslash with awk in OSX
I'm trying to match \N in a field of a csv file.
I've tried
awk -F "|" '($12=="\N") {print}' ./filename.csv
awk -F "|" '($12==\N) {print}' ./filename.csv
awk -F "|" '($12==\\N) {print}' ./filename....
- 221
2
votes
1
answer
2k
views
awk pattern with variable in a bash script
I have problem with command awk in bash
I want to find pattern with variable, but it doesn't work. Can you tell me what's wrong with this line?
awk -F" " "/$PWD/ {print $1,$3}" file.txt
- 611
2
votes
1
answer
3k
views
awk in ssh in su in a command substitution
I am creating a script that will ssh to a host and print all the user accounts and when they will expire.
On a host I can run awk -F':' '{ print $1}' /etc/passwd and it will give me a list of all ...
- 651
2
votes
2
answers
4k
views
Environment variable not expanded inside the command line argument
I have a file user-pid.out2 which has "usernumber" and "process id" as two columns. based on usernumber I want to find corresponding process id. the first two lines below does not show the output ...
- 21