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-20 bytes thanks to @Laikoni
(k#x)0=x (k#x)n=k#(f k=[n|n<-[0..k*k^k],let x#0=1>0;x#n|m<-mod n k:x)$divk=notElem nm k x[]=1>0 xx&&(am:bx)=notElem a b&&x#div b fn k=filter(x.(k#[]))[0..k*k^k]k,[]#n]
Try it online!Try it online!
(k#x)0=x (k#x)n=k#(mod n k:x)$div n k x[]=1>0 x(a:b)=notElem a b&&x b f k=filter(x.(k#[]))[0..k*k^k]
Try it online!
f k=[n|n<-[0..k*k^k],let x#0=1>0;x#n|m<-mod n k=notElem m x&&(m:x)#div n k,[]#n]
