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edited Jun 15, 2020 at 4:22

Jamal

Hereby another 'Pythonic' variant of Jamal & MatthewsMatthew's answer which does not require the use of both range() & len()range() and len():

[sum(L[:i[0]+1]) for i in enumerate(L)]

enumerateenumerate is handy to use since it creates tuples containing the index and value at that index.

Hereby another 'Pythonic' variant of Jamal & Matthews answer which does not require the use of both range() & len():

[sum(L[:i[0]+1]) for i in enumerate(L)]

enumerate is handy to use since it creates tuples containing the index and value at that index.

Hereby another 'Pythonic' variant of Matthew's answer which does not require the use of both range() and len():

[sum(L[:i[0]+1]) for i in enumerate(L)]

enumerate is handy to use since it creates tuples containing the index and value at that index.

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answered Jun 14, 2020 at 10:09

user226095

Hereby another 'Pythonic' variant of Jamal & Matthews answer which does not require the use of both range() & len():

[sum(L[:i[0]+1]) for i in enumerate(L)]

enumerate is handy to use since it creates tuples containing the index and value at that index.