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$\begingroup$ What If I will used a 160 bits key? If I will encrypt a blocksize of 128 bits of plaintext? $\endgroup$goldroger– goldroger2012-04-30 09:15:27 +00:00Commented Apr 30, 2012 at 9:15
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$\begingroup$ key size and block size are independent, you could use a 160 bit key and 128 bit blocksize in rijndael. But why do you want to use a 160 bits key? Why don't you use one of the standard sizes? $\endgroup$CodesInChaos– CodesInChaos2012-04-30 09:16:50 +00:00Commented Apr 30, 2012 at 9:16
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$\begingroup$ so therefore If I will encrypt a plaintext blocksize of 128 bits, I will use only a 32-128 bits of secret key? 192 bits, I will use a 32-192 bits of secret key? 256 bits, I will use a 32-256 bits of secret key? $\endgroup$goldroger– goldroger2012-04-30 09:18:57 +00:00Commented Apr 30, 2012 at 9:18
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$\begingroup$ @JohnPaulParreño That makes no sense at all. AES always uses the full secret key. I don't see how plaintext size and keysize are related. $\endgroup$CodesInChaos– CodesInChaos2012-04-30 09:21:54 +00:00Commented Apr 30, 2012 at 9:21
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$\begingroup$ what? I'm confused, but you said before why don't I use one of the standard sizes, i thought If I will encrypt a 128 bits of plaintext, I can used a 128 bits of key... $\endgroup$goldroger– goldroger2012-04-30 09:26:40 +00:00Commented Apr 30, 2012 at 9:26
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