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Timeline for answer to Relation of Space and Time in Complexity? by David Richerby

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Feb 28, 2014 at 0:04 vote accept EthanLWillis
Feb 27, 2014 at 21:56 comment added David Richerby Yes and no. Remember that every problem in P is also in NP, as you can think of a deterministic TM as a trivial case of a nondeterministic TM (it just only ever makes nondeterministic choices from a single option). Finding an efficient way to be smart about which branch to simulate would certainly be one way of proving P = NP but it's possible that there are other ways, too.
Feb 27, 2014 at 21:35 comment added EthanLWillis Thank you for your reply. So basically what P=NP boils down to is: Is there any way to create a problem in P that is equivalent to a problem in NP by choosing "smartly" which branches of an NTM to simulate on a DTM?
Feb 27, 2014 at 21:03 history answered David Richerby CC BY-SA 3.0