Timeline for Bandwidth of a signal
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18 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 29, 2021 at 4:05 | vote | accept | Jonathan_the_seagull | ||
| Aug 28, 2021 at 20:03 | comment | added | CommunityBot | Please clarify your specific problem or provide additional details to highlight exactly what you need. As it's currently written, it's hard to tell exactly what you're asking. | |
| Aug 28, 2021 at 19:32 | answer | added | Tony Stewart EE since 1975 | timeline score: 1 | |
| Aug 28, 2021 at 19:08 | answer | added | Lewis Kelsey | timeline score: 2 | |
| Aug 28, 2021 at 18:16 | comment | added | Jonathan_the_seagull | No, I am asking whether the bandwidth will change if we had some spectrum which looks like an odd function centred at 0 and confined to -B and +B.(forget the figure that I posted) | |
| Aug 28, 2021 at 18:13 | history | edited | JRE | CC BY-SA 4.0 |
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| Aug 28, 2021 at 18:12 | comment | added | Tony Stewart EE since 1975 | U are asking to make a half sine by multiply f * a pulse of known spectrum. So if you multiply in time domain , analyze f domain with what you know | |
| Aug 28, 2021 at 18:08 | comment | added | Jonathan_the_seagull | @Tony Stewart What if instead of the pulse we either had a truncated sine or a cosine wave located between -B and +B. In this case, would the odd and even properties affect the bandwidth? | |
| Aug 28, 2021 at 18:03 | comment | added | Tony Stewart EE since 1975 | No but 0+/-B is just BW=B, yet for 1000+/-B, BW=2B the difference between signals inside +B and -B is due to phase difference | |
| Aug 28, 2021 at 18:03 | comment | added | Jonathan_the_seagull | @Tony Stewart So, if the spectrum is symmetric about the origin, the bandwidth will always be half the total width of the spectrum? | |
| Aug 28, 2021 at 18:00 | history | edited | Jonathan_the_seagull | CC BY-SA 4.0 |
added 158 characters in body
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| Aug 28, 2021 at 18:00 | comment | added | Tony Stewart EE since 1975 | Ignore your doubt to understand why -B is the same as +B around 0 and always will be until you shift it from 0 | |
| Aug 28, 2021 at 17:57 | comment | added | Jonathan_the_seagull | So, is the bandwidth of the figure I have shown 1 instead of 2Hz? | |
| Aug 28, 2021 at 17:56 | comment | added | Tony Stewart EE since 1975 | Prof is correct and ought to be 99% of the time | |
| Aug 28, 2021 at 17:49 | comment | added | Jonathan_the_seagull | The question was to find the bandwidth of the signal x(t) = sinc^2(t). I took its fourier transform and then convoluted the two rect pulses (graphical convolution) to get a value of (1+f) for 0<f<-1 and a value of (1-f) for 0<f<1. This is how I got the triangular pulse. | |
| Aug 28, 2021 at 17:45 | comment | added | John D | This sounds like a homework problem. We don't give answers to homework problems, but if you show how you tried to solve it or your reasoning and where you got stuck or have doubts, you will likely get some hints. | |
| S Aug 28, 2021 at 17:43 | review | First questions | |||
| Aug 28, 2021 at 20:03 | |||||
| S Aug 28, 2021 at 17:43 | history | asked | Jonathan_the_seagull | CC BY-SA 4.0 |