Timeline for Sums of Consecutive Cubes (Trouble Interpreting Question)
Current License: CC BY-SA 3.0
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| when toggle format | what | by | license | comment | |
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| Oct 12, 2017 at 12:20 | answer | added | Rosie F | timeline score: 0 | |
| Apr 1, 2015 at 3:58 | history | edited | Tito Piezas III |
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| Apr 1, 2015 at 3:55 | comment | added | Tito Piezas III | Note that the next step with 16 consecutive cubes $1^3,2^3,3^3,\dots, 16^3$ yields the equi-partition, $$1^k + 4^k + 6^k + 7^k + 10^k + 11^k + 13^k + 16^k = 2^k + 3^k + 5^k + 8^k + 9^k + 12^k + 14^k + 15^k$$ which is good for $k=0,1,2,3$. See also this post. | |
| Mar 24, 2015 at 10:12 | answer | added | barak manos | timeline score: 2 | |
| Mar 24, 2015 at 9:52 | history | edited | A is for Ambition | CC BY-SA 3.0 |
added 1258 characters in body
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| Mar 24, 2015 at 7:40 | answer | added | David | timeline score: 3 | |
| Mar 24, 2015 at 7:36 | history | asked | A is for Ambition | CC BY-SA 3.0 |