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Oct 31, 2019 at 16:33 comment added MisterH Now that I think of it, if the horizontal coordinate of the center of the circle would always be at 0.5 times the first y-value, then the circle would go through the origin, giving you 2 points, and the third could be easily found because the arc length of the circle-segments between points on the circle would be equivalent to the distance from 0 to the first y-value, and this would be the hypotenuse of the right triangle, so via pythagoras you get your third x-value, and 3 points uniquely define a circle, so you only have to plug in the other y-values, giving you all the x-values...
Oct 29, 2019 at 3:53 comment added David K I would expect to be able to rule out one of the roots. But I think this answer needs to be checked, because when I tried it on an example it did not recover the original differences in $x$ values.
Oct 28, 2019 at 16:10 comment added MisterH Ok if one of the conditions: "These circles touch the Y-axis in 1 place: the first y-value (closest to the origin), where they also touch each other." is incorrect: they cross the Y-axis twice, and if you knew that the horizontal coordinate of the center of the circle would always be at 0.5 times the first y-value, would there be a different solution? Solving for the last equation for t always returns 2 real roots.
Oct 18, 2019 at 22:48 vote accept MisterH
Oct 6, 2019 at 3:40 history edited David K CC BY-SA 4.0
interpretation
Oct 6, 2019 at 3:33 history edited David K CC BY-SA 4.0
interpretation
Oct 6, 2019 at 3:28 history edited David K CC BY-SA 4.0
interpretation
Oct 6, 2019 at 3:22 history edited David K CC BY-SA 4.0
three points are not enough
Oct 6, 2019 at 3:15 history answered David K CC BY-SA 4.0