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Oct 28, 2019 at 12:02 comment added Narasimham @ K Groll Unless $CP=h \tanθ $ is known a priori, we cannot commence this construction. Also please note it comes to the same thing.. $ \cot \theta= \dfrac{m_2-m_1}{1+m_1 m_2}$
Oct 28, 2019 at 11:53 comment added Daniel Mathias Selective vision... Anyway, we still need to find $CQ$ rather than $PQ$
Oct 28, 2019 at 11:24 comment added K Groll @Narasimham Thanks for your answer but I don't quite understand. I used tan 𝜃 = m2−m1/1+m1m2 to get angle ACD and then I had two side lengths and one angle and used SSA and sine law to get the rest. I'm not sure how to establish h or 𝜃 without doing the same.
Oct 28, 2019 at 10:58 comment added Narasimham @DanielMathias OP has given circles of same radius.
Oct 28, 2019 at 10:47 comment added K Groll @DanielMathias this is the approach I took. The above answer works but after finding PQ, CP also needs to be found (unless I misunderstand)
Oct 28, 2019 at 9:53 comment added Daniel Mathias The circles are not given to be congruent, so $AQ=r_1+r_2$. Otherwise this approach is good, though I would let $\theta=\angle ACD$ then use sine rule to find $CQ$
Oct 28, 2019 at 6:58 history undeleted Narasimham
Oct 28, 2019 at 6:54 history deleted Narasimham via Vote
Oct 28, 2019 at 6:54 history answered Narasimham CC BY-SA 4.0