Timeline for On the functional square root of $x^2+1$
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Dec 29, 2020 at 18:12 | comment | added | Gottfried Helms | @Raffaele - well the question of the domain ... I've often seen that problem, and have put it into discussion, but I myself don't have a reliable answer in many cases. So it must be answered case-by-case; usually my analyses are only taken the most simple assumptions for the domain; but at the moment I'm absorbed elsewhere... | |
| Dec 29, 2020 at 18:09 | comment | added | Raffaele | If $f(x)=x^2$ can we say that $f^{(1/2)}=x^{\sqrt 2}$? I am asking because the domain of $x^{\alpha}$ for real exponent is $x>0$ while the domain of $f$ is $\mathbb{R}$ so applying twice $x^{\sqrt 2}$ I get $x^2;\;x>0$ which is not $f(x)$. | |
| Aug 10, 2013 at 9:13 | history | edited | Gottfried Helms | CC BY-SA 3.0 |
added 769 characters in body
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| Jan 4, 2013 at 11:32 | history | edited | Mario Carneiro | CC BY-SA 3.0 |
fixed LaTeX
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| Sep 4, 2010 at 15:11 | history | edited | Gottfried Helms | CC BY-SA 2.5 |
just noticed the better link to mathoverflow
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| Sep 4, 2010 at 14:13 | history | edited | Gottfried Helms | CC BY-SA 2.5 |
extended the explanations
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| Sep 4, 2010 at 13:42 | history | answered | Gottfried Helms | CC BY-SA 2.5 |