Timeline for answer to Solution for the following limit problem by saulspatz
Current License: CC BY-SA 4.0
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| when toggle format | what | by | license | comment | |
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| Apr 12, 2021 at 20:16 | comment | added | saulspatz | @HirakSarkar If you mean how to get $\lim_{x\to\infty}\frac{x+a}{x+b}=1$, you can use L'Hospital, or just divide numerator and denominator by $x$. | |
| Apr 12, 2021 at 20:14 | comment | added | Hirak Sarkar | Your last step is l'hopitals? | |
| Apr 12, 2021 at 20:11 | history | answered | saulspatz | CC BY-SA 4.0 |