Timeline for solution of diophantine equation $y^3 = z^2 - 1$
Current License: CC BY-SA 4.0
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11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 13, 2024 at 6:55 | comment | added | peter petersen | Would it suffices to just check $x=1.$ | |
| S Nov 13, 2024 at 6:51 | history | suggested | Guruprasad |
I removed elementary number theory tag and elliptic curves
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| Nov 13, 2024 at 6:16 | review | Suggested edits | |||
| S Nov 13, 2024 at 6:51 | |||||
| Sep 27, 2022 at 17:48 | answer | added | user887388 | timeline score: 2 | |
| Jun 15, 2022 at 12:19 | comment | added | user25406 | The equation can be rewritten as $y^3=y*y^2=z^2-1=(z-1)(z+1)$. so we have the system $y=z-1$ and $y^2=z+1$ which is easy to see that $y=2$ if $z=3$. It doesn't say anything about other possible solutions. | |
| Jun 15, 2022 at 4:15 | comment | added | Eric Snyder | @DietrichBurde Sadly it's behind a paywall. | |
| Jun 14, 2022 at 21:05 | comment | added | John Omielan | @FredJefferson FYI, using an Approach0 search, I found Proof that $x^2-y^3=1$ has only one solution in the domain of $N^+$? and the AoPS thread Theory of equation. | |
| Jun 14, 2022 at 16:25 | comment | added | J.G. | Nowadays, that conjecture is often called Mihăilescu's theorem. | |
| Jun 14, 2022 at 14:52 | comment | added | Dietrich Burde | Indeed, have a look at Cohn's beautiful proof. | |
| Jun 14, 2022 at 14:41 | comment | added | lulu | See this question | |
| Jun 14, 2022 at 14:38 | history | asked | Fred Jefferson | CC BY-SA 4.0 |