Timeline for Uses of the symmetric derivative $\lim \limits_{h\to 0} \frac{f(x+h)-f(x-h)}{2h}$?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Jul 9, 2013 at 22:51 | history | edited | jimjim | CC BY-SA 3.0 |
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| Jul 15, 2012 at 13:28 | comment | added | Jesse Madnick | @Arjang: It is not assumed that $\delta > 0$. In other words, $\lim_{\delta \to 0} \frac{f(x+\delta) - f(x)}{\delta}$ is a two-sided limit. | |
| Sep 19, 2011 at 6:52 | history | edited | jimjim | CC BY-SA 3.0 |
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| Sep 19, 2011 at 1:24 | comment | added | jimjim | @Didier : but $\frac {f(x+\delta)-f(x)}{\delta}$ is only the left side, I have not seen that $\frac {f(x)-f(x-\delta)}{\delta}$ as a requiremnt, are we talking about the same thing? | |
| Sep 18, 2011 at 23:01 | comment | added | The Chaz 2.0 | Differentiability --> continuity --> LH Limit = RH Limit | |
| Sep 18, 2011 at 21:00 | comment | added | Did | For the usual derivative to exist, it is certainly not enough that the "right hand limit" exists. | |
| Sep 18, 2011 at 20:54 | history | answered | jimjim | CC BY-SA 3.0 |