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Aug 13, 2016 at 13:30 vote accept Chertan
Aug 11, 2016 at 19:50 comment added Michael E2 A side issue, unrelated to the problem: You should avoid starting your symbol names with a capital letter, especially single character variables. Quite a few are reserved symbols used by Mathematica.
Aug 11, 2016 at 19:46 answer added Chris K timeline score: 1
Aug 11, 2016 at 19:32 history edited Michael E2 CC BY-SA 3.0
Improved formatting
Aug 11, 2016 at 19:16 comment added Chertan Sorry, I can't add the screenshot of the function x[[Phi]] due to my reputation. But it has the same view as the equation at the begining of the question.
Aug 11, 2016 at 19:16 history edited Chertan CC BY-SA 3.0
added 142 characters in body
Aug 11, 2016 at 19:07 comment added Chertan @MichaelSeifert yes, I need negative one. Therefore I used the restrictions on phi in the first example
Aug 11, 2016 at 19:04 comment added Chertan @ChrisK definition: x[[Phi]_] := 1/(2 Sqrt[2]) (-2/[Phi] + Log[(1 + [Phi])/(1 - [Phi])]); I also added it to the post as screenshot
Aug 11, 2016 at 19:03 comment added Michael Seifert It looks like your equation $x(\phi) = x_0$ has two solutions for all values of $x_0$, one with positive $\phi$ and one with negative $\phi$. Do you have a preference as to which one is returned?
Aug 11, 2016 at 18:55 comment added Chris K Could you give Mathematica code for your definition of x[\[Phi]]? Could be similar to this question.
Aug 11, 2016 at 18:35 comment added user9660 Welcome to Mathematica.SE! 1) As you receive help, try to give it too, by answering questions in your area of expertise. 2) Take the tour and check the help center! 3) When you see good questions and answers, vote them up by clicking the vote triangles, because the credibility of the system is based on the reputation gained by users sharing their knowledge. Also, please remember to accept the answer, if any, that solves your problem, by clicking the checkmark sign!
Aug 11, 2016 at 18:35 review First posts
Aug 11, 2016 at 18:36
Aug 11, 2016 at 18:34 history asked Chertan CC BY-SA 3.0