Timeline for answer to FindRoot errors by b.gates.you.know.what
Current License: CC BY-SA 3.0
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5 events
| when toggle format | what | by | license | comment | |
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| Dec 9, 2012 at 19:15 | vote | accept | Amatya | ||
| Nov 8, 2012 at 9:08 | comment | added | Amatya | ...phbbhtt.. my brains are fried. Ocfcourse.. I know what badFactor is.. literally ... I can't believe I asked the second part of the question. :) | |
| Nov 8, 2012 at 9:04 | comment | added | b.gates.you.know.what |
As long as neither of sol is 0 then yes, badFactor is finite (but possibly very large).
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| Nov 8, 2012 at 8:53 | comment | added | Amatya |
ok cool. so is the idea that f2(x)=good(x)*bad(x) then if bad(a)!=Infinity and good(a)=0 then a is a solution to f2 ? In my example, badFactor/.sol is around 10^16.. can we say that that's not (or not going to) Infinity?
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| Nov 8, 2012 at 7:31 | history | answered | b.gates.you.know.what | CC BY-SA 3.0 |