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edited Aug 4, 2019 at 12:57

I think the easiest way would be to define(name) the pure function f

f = Sqrt[-1 + Tanh[#1 - #2]^2] &

this givesand use it accordingly

f[x,y] 
(*Sqrt[-1 + Tanh[x - y]^2]*)

I think the easiest way would be

f = Sqrt[-1 + Tanh[#1 - #2]^2] &

this gives

f[x,y] 
(*Sqrt[-1 + Tanh[x - y]^2]*)

I think the easiest way would be to define(name) the pure function f

f = Sqrt[-1 + Tanh[#1 - #2]^2] &

and use it accordingly

f[x,y] 
(*Sqrt[-1 + Tanh[x - y]^2]*)

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answered Aug 4, 2019 at 11:20

Ulrich Neumann

I think the easiest way would be

f = Sqrt[-1 + Tanh[#1 - #2]^2] &

this gives

f[x,y] 
(*Sqrt[-1 + Tanh[x - y]^2]*)