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    $\begingroup$ (+) This is an amazing solution. Each step is very clear. This approach can probably be applied to many questions here. It should be added that for general complex $U$ the initial and the final expressions are not equivalent, but that's a different story. $\endgroup$ Commented 2 days ago
  • $\begingroup$ (+1) Great answer. The way you uncover the required algebraic extension and only then factor is particularly elegant. $\endgroup$ Commented yesterday