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Jul 22, 2015 at 11:08 comment added Michael E2 @Andrei I recall checking something like that for this particular system. What happens if you fold in the plane and axis and solve each system? Something like {y -> 0, x -> z t} and {y -> 0, x -> 0}, and call NSolve on each. That's three calls total to NSolve, but each subsequent one is simpler. But if the way you suggest works, maybe it's simpler.
Jul 22, 2015 at 5:46 comment added Andrei While this solution works for this particular instance of the problem, it is not general. E.g., changevar = {y -> z s, x -> z s t} does not solve the issue anymore, because it misses the hyperplane where y = 0, x = 0, z > 0. For the same reason, the extension of this approach to 4 or more equations can be challenging. Whereas removing simple factors from the Groebner Basis and then running NSolve should always do the trick, I guess.
Jul 21, 2015 at 17:35 comment added Andrei This is also the fastest solution. Removing the factors from the Groebner Basis and then using NSolve takes about 3 sec (was the fastest solution so far). This solution takes about 0.6 sec.
Jul 21, 2015 at 17:31 vote accept Andrei
Jul 14, 2015 at 21:04 history answered Michael E2 CC BY-SA 3.0