Timeline for answer to Effect of abc conjecture on Fermat's Last Theorem by user9072
Current License: CC BY-SA 3.0
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10 events
| when toggle format | what | by | license | comment | |
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| Dec 14, 2018 at 1:10 | comment | added | Đào Thanh Oai | @DietrichBurde Please see mathoverflow.net/questions/303141 | |
| May 17, 2013 at 20:13 | comment | added | user9072 | @Dietrich Burde: I think even for $n \ge 6$, as the inequality is strict. | |
| May 17, 2013 at 20:11 | history | edited | user9072 | CC BY-SA 3.0 |
monir addition in view of an edit to the question
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| May 17, 2013 at 17:52 | comment | added | Dietrich Burde | If we would know that $C_1=1$ for $\epsilon =1$ (and no counterexample is known to that), then FLT would follow for exponents $n\ge 7$. | |
| May 17, 2013 at 17:49 | comment | added | user9072 | You are welcome. Yes in some sense one can consider so to say "two limits" (in $z$ and in $n$) and thus there are in some sense different versions. Yet the finiteness of all solutions (under n> 3) contains all, as if there are only finitely many in total then there is a largest $n$ and a largest $z$ and so on. And, while I read it differently at first, thus my edit, I think the version you link to actually is meant to assert the finiteness of the set of all solutions , ie couples $(z,n)$ and thus contains Lang's. | |
| May 17, 2013 at 17:41 | vote | accept | Favst | ||
| May 17, 2013 at 17:41 | comment | added | Favst | Thanks, quid. So there are two asymptotic versions of FLT which none of my sources cared to distinguish! | |
| May 17, 2013 at 17:27 | history | edited | user9072 | CC BY-SA 3.0 |
added "srongest possible" comment
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| May 17, 2013 at 17:22 | history | edited | user9072 | CC BY-SA 3.0 |
added 62 characters in body
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| May 17, 2013 at 17:16 | history | answered | user9072 | CC BY-SA 3.0 |