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Timeline for answer to Arbitrarily long arithmetic progressions by Lucia

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Jun 23, 2014 at 17:42 comment added The Masked Avenger @shadow10 , searching for Jacobsthal's function on MathOverflow gives a number of hits as well as references to some recent contributions, epecially Thomas Hagedorn's paper in 2009.
Jun 23, 2014 at 12:48 comment added Lucia @shadow10: The OEIS article gives the right function. The bound $K\le P$ follows simply because any interval of $P$ integers contains $\phi(P)$ integers coprime to $P$.
Jun 23, 2014 at 12:40 comment added shadow10 @Lucia could you emphasize a bit on Jacobsthal Function? I searched for it and got oeis.org/wiki/Jacobsthal_function which defines it somehow differently, I think. Could you please clarify? And I also don't see how $K\ge P$ is obvious. Thanks a lot.
Jun 23, 2014 at 8:40 comment added GH from MO Nice explicit argument.
Jun 23, 2014 at 8:39 history edited GH from MO CC BY-SA 3.0
Fixed grammar in the beginning of the second paragraph.
Jun 23, 2014 at 6:17 comment added The Masked Avenger This is a more technical version of what I hoped to convey (which I did not see until after editing my answer). This should convince @GHfromMO if my words do not.
Jun 23, 2014 at 5:01 history answered Lucia CC BY-SA 3.0