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Mar 11, 2019 at 6:18 vote accept T. Amdeberhan
Mar 4, 2019 at 16:26 history edited T. Amdeberhan CC BY-SA 4.0
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Mar 4, 2019 at 7:13 comment added Fedor Petrov Why do you still call it a guess? The exponential generating function from the answer of Richard Stanley proves it.
Mar 4, 2019 at 6:35 history edited T. Amdeberhan CC BY-SA 4.0
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Mar 4, 2019 at 5:38 history became hot network question
Mar 4, 2019 at 5:04 history edited T. Amdeberhan CC BY-SA 4.0
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Mar 4, 2019 at 1:43 answer added Richard Stanley timeline score: 5
Mar 4, 2019 at 0:57 comment added Fedor Petrov If we fix all $n-2k$ diagonal elements, it remains a $2k\times 2k$ squared Pfaffian. It should contain $(2k)!/2^k$ monomials. On purely combinatorial language, the squared Pfaffian monomials correspond to permutations with even cycles only, but we count these permutations up to the change of order of cycles. In other words, we count the spanning subgraphs of $K_{2n}$ in which every component is either an even cycle or an edge.
Mar 3, 2019 at 23:18 history asked T. Amdeberhan CC BY-SA 4.0