Skip to main content
8 events
when toggle format what by license comment
Dec 31, 2019 at 8:36 comment added Harry Altman I see! It's smaller so it makes sense. Thanks!
Dec 29, 2019 at 22:33 comment added Timothy Chow @HarryAltman : Not sure what you mean by the "wrong ordinal." As explained in the paper I mentioned, the validity of induction on $\Gamma_0$ is a natural consequence of Kruskal's theorem. So yes, there is a sense in which Kruskal's theorem is associated with a larger ordinal, but the theorem is also naturally connected with $\Gamma_0$.
Dec 28, 2019 at 22:33 comment added Harry Altman Hold on, wait -- I just realized we've been talking about the wrong ordinal, right? Kruskal's tree theorem is small Veblen ordinal, not $\Gamma_0$, right? May have to go look up this Gallier paper...
Dec 27, 2019 at 5:40 comment added Harry Altman The proof of the Kruskal's Tree Theorem itself needn't involve such an induction, but arguably Schmidt's proof that its type (maximum linearization) is $\Gamma_0$ does? This relates to another question I've been wondering about -- I'm a little unclear here on the connection between type on the one hand & proof-theoretic ordinal on the other; I'm not sure how well that's understood actually... but I guess that's not something to start a discussion on in the comments; maybe I should ask that as a separate question here...)
Dec 27, 2019 at 4:11 comment added Timothy Chow I don't fully understand the distinction that you're trying to draw. The conclusion of Kruskal's tree theorem is that something is a wqo. The "minimal bad sequence" argument is what I'd call an induction argument. I'd call this proof by induction on a wqo, but maybe you reserve that term for a proof that starts with something that is already known to be a wqo, and uses that fact to prove some statement about the wqo other than "this is a wqo"? Anyway you can read the proof and decide for yourself.
Dec 27, 2019 at 1:52 comment added QiRenrui Are this proof of Kruskal's tree theorem uses such a wqo, or it just proves that the trees forms a wqo? And I don't think that means ordinals are not such useful.
Dec 26, 2019 at 22:45 comment added cody I feel like the proof is simply a definition of a WQO, rather than a proof by induction on a WQO. The proof itself is usually in the form of a "minimal bad sequence" argument. I'd also note that it's significantly easier to define and use WQOs and well-founded orders than ordinals, so it might not be quite in the spirit of the question (or maybe it suggests that ordinals are not such useful objects after all...)
Dec 26, 2019 at 18:56 history answered Timothy Chow CC BY-SA 4.0