Imagine a smooth curve $c$ sweeping out a unit-radius disk that is
orthogonal to the curve at every point.
Call the result a tube.
I want to restrict the radius of curvature of $c$ to be at most 1.
I am interested in the behavior of a light ray aimed directly down
the central axis of one end of the tube,
as it bounces with perfect reflection from the interior wall
of the tube.
This could be viewed as a model of an optic fiber,
although I want to treat the light ray as a billiard ball
and not a dispersing wave.
Fibers http://people.csail.mit.edu/~orourke/MathOverflow/Fibers.jpg
Q1. Does the light ray always emerge from the other end?
I believe the answer is Yes, although there can be close calls:
TubeTurns http://people.csail.mit.edu/~orourke/MathOverflow/TubeTurns.jpg
I would be interested in a succinct, convincing proof
(or a counterexample!).
Perhaps I should stipulate that if the ray hits a
boundary singularity (as it nearly does above), it dies;
otherwise it could pass through the center of curvature
and reflect to its own reversal.
Q1 Answer: Yes if $c$ is $C^\infty$ (Dimitri Panov), Not necessarily if $c$ is $C^2$ (Anton Petrunin).
I explored one particular, maximally convoluted, snake-like tube,
composed of alternating semicircles of radius 2 (so the central
curve $c$ has curvature 1):
Rays20 http://people.csail.mit.edu/~orourke/MathOverflow/Rays20.jpg
The lightray behaves seemingly chaotically,
although when I look at the angles the rays make with the $(+x)$-axis,
there is a striking distribution.
Here is a histogram for a tube composed of 1000 semicircles:
Histogram http://people.csail.mit.edu/~orourke/MathOverflow/Histogram1000.jpg
Q2. Can you offer an explanation for the observed distribution of ray orientations? Why is the angle $\pm 17^\circ$ so prominent, and there are no ray angles whose absolute value lies within $[19^\circ,111^\circ]$? There are approximately 1.55 ray bounces per semicircle: Why? Is this approaching $\frac{3}{2}$? Or $\frac{\pi}{2}$?
Ideas/insights welcomed—Thanks!
Q2 Answer: Dimitri Panov's remarks and the phase portrait below show that likely the ray trajectory is quasiperiodic, which explains the angle histogram, which is, in a sense, a projection of the phase portrait.