Timeline for answer to Tweetable way to see that Willmore energy is Möbius invariant? by Yuri Vyatkin
Current License: CC BY-SA 3.0
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| Jun 16, 2012 at 22:08 | comment | added | Glen Wheeler | The Willmore energy is not invariant under inversions centred at some point on the image -- this is well-known. Some energy is lost depending on density. Similarly, images which stretch off to infinity gain energy under inversion. | |
| Jun 15, 2012 at 20:20 | comment | added | Sebastian | @Will, fuzzytron. It is even true for conformal changes of the metric, not only Moebius transformations, as was shown in "Weiner, J., (1978) On a problem of Chen, Willmore, et al., Indiana University Mathematical Journal." | |
| Jun 15, 2012 at 3:46 | comment | added | Will Jagy | @fuzzytron, conformal transformations of $\mathbb R^3.$ These come from stereographic projection to $\mathbb S^3,$ some isometry there, then stereographic projection back. | |
| Jun 14, 2012 at 22:26 | history | edited | Yuri Vyatkin | CC BY-SA 3.0 |
fixed another typo
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| Jun 14, 2012 at 22:20 | history | edited | Yuri Vyatkin | CC BY-SA 3.0 |
Corrected minor typos; added an edit to address the comments.
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| Jun 14, 2012 at 16:07 | comment | added | TerronaBell | Something is not quite right here - you would claim that Willmore energy is not only Möbius invariant but actually conformally invariant? But that is not true - consider two different conformal immersions of the sphere. They will not in general have the same Willmore energy, but one is certainly a conformal transformation of the other since there is only one conformal structure on $S^2$. | |
| Jun 14, 2012 at 11:59 | history | answered | Yuri Vyatkin | CC BY-SA 3.0 |