10
$\begingroup$

Given a cocomplete category $C$, is there an example of an object which is small but not compact?

I am working with the following definitions of small and compact:

Given a cardinal $\kappa$ one says that an object $X$ is $\kappa$-compact, if ${\rm Hom}(X,-)$ commutes with $\kappa$-filtered colimits. One says $X$ is $\kappa$-small if the same happens if indexing category of the colimit is an ordinal.

small means $\kappa$-small for some $\kappa$

compact means $\kappa$-compact for some $\kappa$

$\endgroup$
1
  • 4
    $\begingroup$ See Exercise 1.c(4) in "Locally presentable and acessible categories", Adámek & Rosicky. $\endgroup$ Commented Oct 22, 2015 at 21:36

1 Answer 1

11
$\begingroup$

There is no difference for $\kappa = \aleph_0$. The point is that you can build colimits for filtered diagrams using just colimits for chains.

  1. Every filtered category $\mathcal{J}$ admits a cofinal directed diagram, i.e. a cofinal functor $\mathcal{I} \to \mathcal{J}$ where $\mathcal{I}$ is directed.
  2. Every countable directed poset $\mathcal{I}$ admits a cofinal $\omega$-chain: just take an enumeration of the elements of $\mathcal{I}$ and repeatedly use directedness to get a cofinal chain of length $\omega$.
  3. Every directed poset $\mathcal{I}$ of cardinality $\lambda$ is the union of a $\lambda$-chain of directed subposets of cardinality $< \lambda$. (Observe that every infinite subset $S \subseteq \mathcal{I}$ is contained in a directed subposet of $\mathcal{I}$ of the same cardinality as $S$.)

Thus, by induction, every directed diagram in $\mathcal{C}$ has a colimit constructed using only colimits for chains.

It is tempting to try to generalise this to regular cardinals $\kappa > \aleph_0$, but the subtlety is in (3): in general, $\kappa < \lambda$ is not enough to imply that every subset $S$ of a $\kappa$-directed poset $\mathcal{I}$ of cardinality $< \lambda$ is contained in a $\kappa$-directed subposet of $\mathcal{I}$ of cardinality $< \lambda$. (For this, we need $\kappa \triangleleft \lambda$; see Theorem 2.11 in [Locally presentable and accessible categories].)

I suppose the point is that, for the purposes of the small object argument, $\kappa$-smallness suffices. But one often gets $\kappa$-compactness as well.

$\endgroup$
4
  • 1
    $\begingroup$ This shows what goes wrong if you try to prove that they are equivalent. But it would still be good to see a specific counterexample, as the question asks for! $\endgroup$ Commented Dec 3, 2014 at 16:52
  • $\begingroup$ It would be good to know if $\kappa$-smallness and $\kappa$-compactness really are different. But given that $\aleph_1 \not\triangleleft \aleph_{\omega + 1}$ is basically the smallest non-example of $\kappa \triangleleft \lambda$, it's probably going to be quite intricate... $\endgroup$ Commented Dec 3, 2014 at 17:42
  • 1
    $\begingroup$ Thanks Zhen for your answer. Another issue with generalising 3. is that $\lambda$ that appears may not be $\kappa$-filtered. does one face similar difficulty if one tries to prove $\kappa$-smallness is $\gamma$-compactness for some large enough cardinal $\gamma$? $\endgroup$ Commented Dec 4, 2014 at 1:22
  • 2
    $\begingroup$ I would think so. But that claim is even harder to disprove because it is vacuous in a locally presentable category. $\endgroup$ Commented Dec 4, 2014 at 7:34

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.