Skip to main content
Tweeted twitter.com/StackPhysics/status/805234515635486724
added 7 characters in body
Source Link
Steeven
  • 53.4k
  • 15
  • 108
  • 203

Ohm's law states that  electric current is directly proportional to voltage provided that physical conditions like temperature remain constant i.e.
$$V = IR$$

On the other hand,

$$\text{Power = Voltage} \times \text{Current}$$

So here it seems that the higher the voltage, the lower is the current, provided that the power remains constant (i.e. current is inversely proportional to the voltage here which is against Ohm's Law.).

Now my question is how do physicists explain this apparent contradiction? Or maybe this not a contradiction because I am analysing things incorrectly?

P.S.: I am a tenth grade student so please refrain from the usage of highly complicated terminologies in your answers.

Ohm's law states that  electric current is directly proportional to voltage provided that physical conditions like temperature remain constant i.e.
$$V = IR$$

On the other hand,

$$\text{Power = Voltage} \times \text{Current}$$

So here it seems that higher the voltage lower is the current provided that the power remains constant (i.e. current is inversely proportional to the voltage here which is against Ohm's Law.).

Now my question is how do physicists explain this apparent contradiction? Or maybe this not a contradiction because I am analysing things incorrectly?

P.S.: I am a tenth grade student so please refrain from the usage of highly complicated terminologies in your answers.

Ohm's law states that  electric current is directly proportional to voltage provided that physical conditions like temperature remain constant i.e.
$$V = IR$$

On the other hand,

$$\text{Power = Voltage} \times \text{Current}$$

So here it seems that the higher the voltage, the lower the current, provided that the power remains constant (i.e. current is inversely proportional to the voltage here which is against Ohm's Law.).

Now my question is how do physicists explain this apparent contradiction? Or maybe this not a contradiction because I am analysing things incorrectly?

P.S.: I am a tenth grade student so please refrain from the usage of highly complicated terminologies in your answers.

deleted 5 characters in body; edited tags; edited title
Source Link
Qmechanic
  • 226k
  • 52
  • 647
  • 2.6k

Contradiction in Ohm's Law and relation P=VI$P=VI$

Ohm's law states that  electric current is directly proportional to voltage providedprovided that physical conditions like temperature remain constant i.e.
$$V = IR$$

On the other hand  ,

$$\text{Power = Voltage} \times \text{Current}$$

So here it seems that higher the voltage lower is the current provided that the power remains constant (i.e. current is inversely proportional to the voltage here which is against Ohm's Law.)  .

Now my question is how do physicists explain this apparent contradiction  ? Or maybe this not a contradiction because I am analysing things incorrectly?

P.S.  : I am a tenth grade student so please refrain from the usage of highly complicated terminologies in your answers.

Contradiction in Ohm's Law and relation P=VI

Ohm's law states that  electric current is directly proportional to voltage provided that physical conditions like temperature remain constant i.e.
$$V = IR$$

On the other hand  ,

$$\text{Power = Voltage} \times \text{Current}$$

So here it seems that higher the voltage lower is the current provided that the power remains constant (i.e. current is inversely proportional to the voltage here which is against Ohm's Law.)  .

Now my question is how do physicists explain this apparent contradiction  ? Or maybe this not a contradiction because I am analysing things incorrectly?

P.S.  : I am a tenth grade student so please refrain from the usage of highly complicated terminologies in your answers.

Contradiction in Ohm's Law and relation $P=VI$

Ohm's law states that  electric current is directly proportional to voltage provided that physical conditions like temperature remain constant i.e.
$$V = IR$$

On the other hand,

$$\text{Power = Voltage} \times \text{Current}$$

So here it seems that higher the voltage lower is the current provided that the power remains constant (i.e. current is inversely proportional to the voltage here which is against Ohm's Law.).

Now my question is how do physicists explain this apparent contradiction? Or maybe this not a contradiction because I am analysing things incorrectly?

P.S.: I am a tenth grade student so please refrain from the usage of highly complicated terminologies in your answers.

Question Protected by Qmechanic

Ohm's law states that  electric current is directly proportional to voltage provided that physical conditions like temperature remain constant i.e.
V = IR$$V = IR$$

On the other hand ,

Power = Voltage * Current$$\text{Power = Voltage} \times \text{Current}$$

So here it seems that higher the voltage lower is the current provided that the power remains constant (i.e. current is inversely proportional to the voltage here which is against Ohm's Law.) .

Now my question is how do physicists explain this apparent contradiction ? Or maybe this not a contradiction because I am analysing things incorrectly?

P.S. : I am a tenth grade student so please refrain from the usage of highly complicated terminologies in your answers.

Ohm's law states that  electric current is directly proportional to voltage provided that physical conditions like temperature remain constant i.e.
V = IR

On the other hand ,

Power = Voltage * Current

So here it seems that higher the voltage lower is the current (i.e. current is inversely proportional to the voltage here which is against Ohm's Law.) .

Now my question is how do physicists explain this apparent contradiction ? Or maybe this not a contradiction because I am analysing things incorrectly?

P.S. : I am a tenth grade student so please refrain from the usage of highly complicated terminologies in your answers.

Ohm's law states that  electric current is directly proportional to voltage provided that physical conditions like temperature remain constant i.e.
$$V = IR$$

On the other hand ,

$$\text{Power = Voltage} \times \text{Current}$$

So here it seems that higher the voltage lower is the current provided that the power remains constant (i.e. current is inversely proportional to the voltage here which is against Ohm's Law.) .

Now my question is how do physicists explain this apparent contradiction ? Or maybe this not a contradiction because I am analysing things incorrectly?

P.S. : I am a tenth grade student so please refrain from the usage of highly complicated terminologies in your answers.

added 122 characters in body; added 4 characters in body; added 1 character in body
Source Link
user116688
user116688
Loading
Source Link
user116688
user116688
Loading