Um ... my two cents....

I don't see where does Ohm's law even talk about power? All it talks about is that V=IR irrespective of the power consumed.

If voltage is high then current is low, but to maintain that low current with the high voltage you need high resistance. E.g. for a deltaV of 10V and 1 A current, u need a 10 Ohm resistor or rating higher than 10W (10Vx1A) of higher.

If you happen to put a 5 Ohm resistor across 10V then you will get 2A current and your power (i.e. heat generated) in the resistor will be 20W. Conversely if you want to retain the power of 10W with 2A then you need a 2.5 Ohm resistor which will give you 2.5Ohmx2A = 5V voltage drop and hence 5Vx2A = 10W power.