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Steeven
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The thing is that proportionality means a constant in the formula. $R$ is a constant, but $P$ isn't.

  • Someone (Ohm) found out that $V$ is proportional to $I$: $$V \propto I$$ He found out by testing and experimenting. Everytime $V$ was doubled, $I$ was also doubled as well. This is what is called (direct) proportionality. We can write it with a proportionality constant, for example called $R$: $$V=RI$$ $R$ is constant, which causes the doubling of $V$ in our circuit to double $I$ as well.

  • Someone then also found the relationship: $$P=VI$$ by testing and experimenting. And yes, we could write this as: $$V=P\frac1I$$ which at first sight looks like inverse proportionality. Double the $V$ should then half the $I$.
    But $P$ is not constant. If we change $V$ in our circuit, both $I$ and $P$ change as well. Doubling $V$ does not half the $I$.

Conclusion is that $R$ is a proportionality constant, while $P$ certainly isn't (because it isn't constant). It looks like inverse proportionality at first sight, but isn't.

The thing is that proportionality means a constant in the formula. $R$ is a constant, but $P$ isn't.

  • Someone (Ohm) found out that $V$ is proportional to $I$: $$V \propto I$$ He found out by testing and experimenting. Everytime $V$ was doubled, $I$ was also doubled. This is what is called (direct) proportionality. We can write it with a proportionality constant, for example called $R$: $$V=RI$$ $R$ is constant, which causes the doubling of $V$ in our circuit to double $I$ as well.

  • Someone then also found the relationship: $$P=VI$$ by testing and experimenting. And yes, we could write this as: $$V=P\frac1I$$ which at first sight looks like inverse proportionality. Double the $V$ should then half the $I$.
    But $P$ is not constant. If we change $V$ in our circuit, both $I$ and $P$ change as well. Doubling $V$ does not half the $I$.

Conclusion is that $R$ is a proportionality constant, while $P$ certainly isn't (because it isn't constant). It looks like inverse proportionality at first sight, but isn't.

The thing is that proportionality means a constant in the formula. $R$ is a constant, but $P$ isn't.

  • Someone (Ohm) found out that $V$ is proportional to $I$: $$V \propto I$$ He found out by testing and experimenting. Everytime $V$ was doubled, $I$ doubled as well. This is what is called (direct) proportionality. We can write it with a proportionality constant, for example called $R$: $$V=RI$$ $R$ is constant, which causes the doubling of $V$ in our circuit to double $I$ as well.

  • Someone then also found the relationship: $$P=VI$$ by testing and experimenting. And yes, we could write this as: $$V=P\frac1I$$ which at first sight looks like inverse proportionality. Double the $V$ should then half the $I$.
    But $P$ is not constant. If we change $V$ in our circuit, both $I$ and $P$ change as well. Doubling $V$ does not half the $I$.

Conclusion is that $R$ is a proportionality constant, while $P$ certainly isn't (because it isn't constant). It looks like inverse proportionality at first sight, but isn't.

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Steeven
  • 53.4k
  • 15
  • 108
  • 203

The thing is that proportionality means that there is a constant in the formula. $R$ is a constant, but $P$ isn't.

  • Someone (Ohm) found out that $V$ is proportional to $I$: $$V \propto I$$ That just means that when you doubleHe found out by testing and experimenting. Everytime $V$ was doubled, you also double $I$ was also doubled. Therefor youThis is what is called (direct) proportionality. We can write thisit with a proportionality constant, which we happen to callfor example called $R$: $$V=RI$$ This $R$ is then interpretted as a resistance. But $R$ is constant. Therefor you can double, which causes the doubling of $V$ in yourour circuit and that gives you theto double $I$ as well.

  • Someone then also found the relationship: $$P=VI$$ Andby testing and experimenting. And yes, we could also write this as: $$V=P\frac1I$$ which at first sight looks like inverse proportionality. That would mean that doubleDouble the $V$ givesshould then half the $I$.
    But $P$ is not constant. If Iwe change $V$ in myour circuit, I will se that both $V$ and$I$ and $P$ changeschange as well. When doublingDoubling $V$, I don't get does not half the $I$.

Conclusion is that $R$ is a proportionality constant, while $P$ certainly isn't (because it isn't constant). The inversedIt looks like inverse proportionality relationship appeared to be not trueat first sight, but isn't.

The thing is that proportionality means that there is a constant in the formula. $R$ is a constant, but $P$ isn't.

  • Someone (Ohm) found out that $V$ is proportional to $I$: $$V \propto I$$ That just means that when you double $V$, you also double $I$. Therefor you can write this with a proportionality constant, which we happen to call $R$: $$V=RI$$ This $R$ is then interpretted as a resistance. But $R$ is constant. Therefor you can double the $V$ in your circuit and that gives you the double $I$.

  • Someone then also found the relationship: $$P=VI$$ And yes, we could also write this as: $$V=P\frac1I$$ which at first sight looks like inverse proportionality. That would mean that double the $V$ gives half the $I$.
    But $P$ is not constant. If I change $V$ in my circuit, I will se that both $V$ and $P$ changes. When doubling $V$, I don't get half the $I$.

Conclusion is that $R$ is a proportionality constant, while $P$ certainly isn't (because it isn't constant). The inversed proportionality relationship appeared to be not true.

The thing is that proportionality means a constant in the formula. $R$ is a constant, but $P$ isn't.

  • Someone (Ohm) found out that $V$ is proportional to $I$: $$V \propto I$$ He found out by testing and experimenting. Everytime $V$ was doubled, $I$ was also doubled. This is what is called (direct) proportionality. We can write it with a proportionality constant, for example called $R$: $$V=RI$$ $R$ is constant, which causes the doubling of $V$ in our circuit to double $I$ as well.

  • Someone then also found the relationship: $$P=VI$$ by testing and experimenting. And yes, we could write this as: $$V=P\frac1I$$ which at first sight looks like inverse proportionality. Double the $V$ should then half the $I$.
    But $P$ is not constant. If we change $V$ in our circuit, both $I$ and $P$ change as well. Doubling $V$ does not half the $I$.

Conclusion is that $R$ is a proportionality constant, while $P$ certainly isn't (because it isn't constant). It looks like inverse proportionality at first sight, but isn't.

Source Link
Steeven
  • 53.4k
  • 15
  • 108
  • 203

The thing is that proportionality means that there is a constant in the formula. $R$ is a constant, but $P$ isn't.

  • Someone (Ohm) found out that $V$ is proportional to $I$: $$V \propto I$$ That just means that when you double $V$, you also double $I$. Therefor you can write this with a proportionality constant, which we happen to call $R$: $$V=RI$$ This $R$ is then interpretted as a resistance. But $R$ is constant. Therefor you can double the $V$ in your circuit and that gives you the double $I$.

  • Someone then also found the relationship: $$P=VI$$ And yes, we could also write this as: $$V=P\frac1I$$ which at first sight looks like inverse proportionality. That would mean that double the $V$ gives half the $I$.
    But $P$ is not constant. If I change $V$ in my circuit, I will se that both $V$ and $P$ changes. When doubling $V$, I don't get half the $I$.

Conclusion is that $R$ is a proportionality constant, while $P$ certainly isn't (because it isn't constant). The inversed proportionality relationship appeared to be not true.