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$\begingroup$ Related question by OP: physics.stackexchange.com/q/32110/2451 $\endgroup$Qmechanic– Qmechanic ♦2012-07-17 21:18:15 +00:00Commented Jul 17, 2012 at 21:18
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$\begingroup$ Feynman simply means that the coordinates $x_i$ that contribute most strongly to the integral will be the ones with highest probability should one inquire about the particle's position at some intermediate time. $\endgroup$Emilio Pisanty– Emilio Pisanty2012-08-11 23:29:46 +00:00Commented Aug 11, 2012 at 23:29
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$\begingroup$ Cross-posted from mathoverflow.net/q/102415 $\endgroup$Qmechanic– Qmechanic ♦2012-10-26 21:26:19 +00:00Commented Oct 26, 2012 at 21:26
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