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$\begingroup$ So if I calculated the speed of particle after the radius has been reduced down to 0.5 it would turn out to be $2v$, where $v$ is the original speed? Is there a formula that I can use? $\endgroup$

user5539357
– user5539357

2020-01-26 09:06:21 +00:00
Commented Jan 26, 2020 at 9:06
$\begingroup$ @user55 I have modified my answer to accommodate your comment. $\endgroup$

user249968
– user249968

2020-01-26 09:51:44 +00:00
Commented Jan 26, 2020 at 9:51
$\begingroup$ Actually I was thinking about a formula that doesn't use the conservation of angular momentum. The conservation rule is great because it simplifies the calculations, but I was thinking how much more complicated it would be if I were to calculate the new speed without refering to the law of conservation ofangular momentum and calculating the force component parallel to the velocity vector. $\endgroup$

user5539357
– user5539357

2020-01-26 10:18:48 +00:00
Commented Jan 26, 2020 at 10:18
$\begingroup$ @user5539357 you can ask a separate question for that. $\endgroup$

user249968
– user249968

2020-01-26 10:31:03 +00:00
Commented Jan 26, 2020 at 10:31
$\begingroup$ So the extra kinetic energy comes from the work being done by that force? $\endgroup$

Outis Nemo
– Outis Nemo

2024-07-05 12:14:41 +00:00
Commented Jul 5, 2024 at 12:14

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