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  • $\begingroup$ If you had to guess as to what the square of the momentum operator looked like, what would you guess? $\endgroup$ Commented Mar 22, 2013 at 20:01
  • $\begingroup$ How were you able to derive this relationship for the expectation value? How is that approach not applicable to $\hat p^2$? $\endgroup$ Commented Mar 22, 2013 at 20:16
  • $\begingroup$ I derived it from $d\langle x \rangle/dt$ using 2 partial derivation, some u-substitutions and derivation of a product. It took me 2 days to calculate it. I did it like Griffith in his book... $\endgroup$ Commented Mar 22, 2013 at 22:54