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$\begingroup$ In the linked posts, the bound state under consideration are normalized eigenstates of the Hamiltonian. $\endgroup$

SolubleFish
– SolubleFish

2023-09-25 11:14:42 +00:00
Commented Sep 25, 2023 at 11:14
$\begingroup$ @SolubleFisch Indeed, my post above refers to the general case. I know the other answers. and yours in particular concernin eigevectors of the Hamiltonian in 1D. The above issue, conversely, seems to refer to the general case... Or, at least, it was my interpretation. $\endgroup$

Valter Moretti
– Valter Moretti

2023-09-25 12:02:49 +00:00
Commented Sep 25, 2023 at 12:02

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