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$\begingroup$ Thank you for the explanation. Since the moment does not have a specified point of action is it correct to take it anywhere perpendicular to the current carrying loop in the mentioned example for the sake of solving numericals(example was attached in the post). $\endgroup$

Ritvik Bansal
– Ritvik Bansal

2025-06-29 18:59:14 +00:00
Commented Jun 29, 2025 at 18:59
1

$\begingroup$ @RitvikBansal If the magnetic field is uniform over the loop then yes. If the magnetic field is not uniform then it is not of much use to define a magnetic moment like this. $\endgroup$

Kapil
– Kapil

2025-06-29 19:20:40 +00:00
Commented Jun 29, 2025 at 19:20

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