Timeline for How is this ratio formula for two conducting balls true?
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| yesterday | comment | added | Paulo Rodriguez | $q'_a+q'_b=q_a+q_b$ is always true; that's conservation of charge. $q'_ar_a=q'_br_b$ is the equilibrium condition. | |
| yesterday | comment | added | JAB | Ah, so is the $q'_{a} + q'_{b} = q_{a} + q_{b}$ incorrect? | |
| yesterday | vote | accept | JAB | ||
| yesterday | history | answered | Paulo Rodriguez | CC BY-SA 4.0 |