Timeline for answer to Smallest polyomino adjacent to 3 copies by new Q Open Wid
Current License: CC BY-SA 4.0
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13 events
| when toggle format | what | by | license | comment | |
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| Jul 24, 2023 at 17:44 | comment | added | new Q Open Wid | @DmitryKamenetsky late, but yes. I deliberately made the lengths different for prettification purposes. | |
| Jul 24, 2023 at 5:34 | comment | added | justhalf | @DmitryKamenetsky all the sides can be reduced until only one pillar, yeah, it seems | |
| Jul 24, 2023 at 5:34 | comment | added | justhalf | @newQOpenWid, K4 is planar. A triangle with a point inside it. | |
| Jul 24, 2023 at 3:14 | comment | added | Dmitry Kamenetsky | I feel that the horizontal sections can be made the same size as the vertical sections? | |
| Jul 23, 2023 at 23:06 | comment | added | Dmitry Kamenetsky | made a new puzzle for the new question | |
| Jul 23, 2023 at 23:00 | comment | added | new Q Open Wid | @DmitryKamenetsky I'm not sure... $K_4$ appears to have some edges that cross each other; it would be akin to forcing diagonal meetings on one diagonal and then the other being blocked off. | |
| Jul 23, 2023 at 22:51 | comment | added | Dmitry Kamenetsky | I am now wondering if there is a P that only requires 4 copies? Maybe I'll make another puzzle for it | |
| Jul 23, 2023 at 22:50 | vote | accept | Dmitry Kamenetsky | ||
| Jul 23, 2023 at 22:48 | comment | added | Dmitry Kamenetsky | This is a brilliant answer! I didn't even know that was possible. | |
| Jul 23, 2023 at 21:47 | history | edited | new Q Open Wid | CC BY-SA 4.0 |
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| Jul 23, 2023 at 21:18 | comment | added | AxiomaticSystem | rot13(Jung jbhyq gur gbc ebj bs n zbabzvab fbyhgvba ybbx yvxr?) | |
| Jul 23, 2023 at 21:08 | history | edited | new Q Open Wid | CC BY-SA 4.0 |
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| Jul 23, 2023 at 17:06 | history | answered | new Q Open Wid | CC BY-SA 4.0 |