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1$\begingroup$ Well done! That was incredibly fast. $\endgroup$Dmitry Kamenetsky– Dmitry Kamenetsky2025-08-03 13:45:58 +00:00Commented Aug 3, 2025 at 13:45
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$\begingroup$ @DmitryKamenetsky thanks to Sunday chilling :) $\endgroup$Oray– Oray2025-08-03 13:46:37 +00:00Commented Aug 3, 2025 at 13:46
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1$\begingroup$ Thanks for the extra details. $\endgroup$Dmitry Kamenetsky– Dmitry Kamenetsky2025-08-03 19:13:29 +00:00Commented Aug 3, 2025 at 19:13
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$\begingroup$ Also a +1 from me. I did make a simplification in your last spoiler, identifying the common value as a 4th root of 3^(27)/2^(27) instead of an eighth root of 3^(54)/2^(54). $\endgroup$Oscar Lanzi– Oscar Lanzi2025-08-04 12:10:11 +00:00Commented Aug 4, 2025 at 12:10
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