Timeline for answer to The clearly wrong proof by harpematt
Current License: CC BY-SA 3.0
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| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 20, 2016 at 9:11 | comment | added | Artyer | Wouldn't it be (For the left) $10x-1x=\log_{10}(\frac{10x}{1x})=\log_{10}(10)=1$, and not $1x$? $10x-1x\neq (10-1)\times x$ with this meaning of subtract. | |
| Mar 19, 2016 at 13:55 | review | First posts | |||
| Mar 19, 2016 at 14:06 | |||||
| Mar 19, 2016 at 13:54 | history | answered | harpematt | CC BY-SA 3.0 |