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Timeline for answer to The Bunny's Tour by d'alar'cop

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Jun 17, 2020 at 8:22 history edited CommunityBot
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Jul 12, 2017 at 16:19 comment added warspyking :) ${}{}{}{}{}$
Jul 11, 2017 at 14:38 comment added d'alar'cop @warspyking indeed.. the good old days :D hi btw
Apr 13, 2017 at 12:50 history edited CommunityBot
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Feb 3, 2017 at 3:38 comment added warspyking Ah memories. ${}$
Jan 15, 2016 at 5:34 comment added justhalf The terminologies are a bit confusing indeed, but eventually I get it. And wow, this is the largest bounty I've ever seen on this site.
May 30, 2015 at 0:05 comment added Brian Yes, I think it does.
May 28, 2015 at 2:53 comment added Brian Sorry, still not getting it. If a hops over b then b ends up where a was before. But if instead b hops over a then b does not end up where a was before -- instead b ends up two squares away from a's original location. Have I misunderstood?
May 22, 2015 at 9:46 history bounty awarded Rand al'Thor
May 21, 2015 at 18:07 comment added d'alar'cop @Brian you have missed the essence of the argument or maybe you misunderstood the rules... a hop does leave b where a was before AND if b is now where a was then he is on the walk (he may extend the walk by moving to more squares of the same colour)
May 21, 2015 at 16:41 comment added Brian I don't understand several steps in the section "Answer" -- it looks like it is incorrect. First: it's possible for $\alpha$ to leave walk $w$ by a hop that doesn't put $\beta$ on walk $w$: just have $\beta$ hop over $\alpha$. Second, even if $\beta$ does end up on walk $w$, he doesn't have to stay on walk $w$ -- he can step to any square of the same color. I think this completely refutes your answer.
Dec 4, 2014 at 5:04 comment added d'alar'cop @miracle173 if you still want to discuss this... chat.stackexchange.com/rooms/19166/bunny-tour
Dec 4, 2014 at 4:19 history edited d'alar'cop CC BY-SA 3.0
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Nov 3, 2014 at 22:34 comment added miracle173 I hope we can continue this in a chat. I opened a chat room chat.stackexchange.com/rooms/18372/the-bunnys-tour
Nov 3, 2014 at 10:22 comment added d'alar'cop @miracle173 "all squares that have the same color as s can be reached by a sequence of (diagonal) steps" - Not without visiting the same square again. "a lot of sentences in the paragraph titled "answer" look suspicious to me" - If you could be more precise maybe there's something useful to be added - otherwise, I'm not sure what I should do
Nov 3, 2014 at 9:44 comment added miracle173 all squares that have the same color as s can be reached by a sequence of (diagonal) steps. But also a lot of sentences in the paragraph titled "answer" look suspicious to me.
Nov 3, 2014 at 9:15 history edited d'alar'cop CC BY-SA 3.0
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Nov 1, 2014 at 20:32 comment added d'alar'cop @miracle173 you're right about the misuse in lemma 1. as for the rest I must respectfully disagree
Nov 1, 2014 at 20:31 history edited d'alar'cop CC BY-SA 3.0
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Nov 1, 2014 at 20:17 comment added miracle173 in vocabulary you define walk as the diagonal movement movement of a bunny by one field. In the first part of lemma 1 you use "walk" in this way again . In the second part of lemma 1 you say it took 4 walks to cover the fields of a board. Here you use "walk" in a different way. In lemma 2 you use "walk" again to define "reachable". If you use "walk" in the first sense than your lemma 2 is wrong. If you use it in the second sense then your lemma does not make sense at all because there is not only one partitioning of the fields of one color into four "walks".
Nov 1, 2014 at 14:27 history edited d'alar'cop CC BY-SA 3.0
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Nov 1, 2014 at 11:29 vote accept warspyking
Nov 1, 2014 at 5:29 history edited d'alar'cop CC BY-SA 3.0
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Nov 1, 2014 at 5:23 comment added d'alar'cop @warspyking Hey warspy, I moved the answer into the bounty answer
Nov 1, 2014 at 5:22 history edited d'alar'cop CC BY-SA 3.0
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Oct 31, 2014 at 5:23 comment added d'alar'cop @warspyking I think I got it - I used a fresh answer
Oct 30, 2014 at 11:11 comment added warspyking Alright as long as you're working on it, I'm patiently waiting for this.
Oct 30, 2014 at 10:55 comment added d'alar'cop @warspyking lol. I'm still mulling it over. I've made progress...
Oct 30, 2014 at 10:31 comment added warspyking Waiting for solid stuff...
Oct 26, 2014 at 14:39 comment added warspyking Good. I can't wait to see a solid answer to "Bunny's Tour"
Oct 26, 2014 at 14:31 comment added d'alar'cop @warspyking i promise i will
Oct 26, 2014 at 13:53 history bounty awarded warspyking
Oct 26, 2014 at 13:53 comment added warspyking I'll award it to you since there's 4 hours left, but make sure to make it solid eventually
Oct 26, 2014 at 8:27 comment added d'alar'cop @warspyking I'll probably get it done eventually - however I don't expect to beat the expiration of the bounty :( too busy
Oct 26, 2014 at 7:27 comment added d'alar'cop @warspyking I've been thinking about it... this latest thing I noticed is quite weird to me. i.e. that a bunny does not really visit the square he is in after he is hopped over. Because this means he sort of visits it twice physically - but did not chose to move there and was not one of his 63 moves - so doesn't count.
Oct 25, 2014 at 21:26 comment added warspyking Hurry up and "turn this into something solide" the bounty ends in 20 hours!
Oct 23, 2014 at 15:28 comment added d'alar'cop @Ali Really? OK, I think I see the comment you're referring to. That changes things a bit
Oct 23, 2014 at 15:21 comment added Ali "3 squares are "involved" in a hop. And one of them will be guaranteed to be red after a hop." From comment from warspyking elsewhere on the page, that square won't go red, because a bunny only paints squares he chooses to move to.
Oct 23, 2014 at 14:22 history edited d'alar'cop CC BY-SA 3.0
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Oct 22, 2014 at 19:40 comment added warspyking "(these first 3 are because the bunny's counterpart cannot each a hopping square)" --Why does this have it's own point?
Oct 22, 2014 at 11:48 history edited d'alar'cop CC BY-SA 3.0
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Oct 22, 2014 at 10:59 history edited d'alar'cop CC BY-SA 3.0
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Oct 22, 2014 at 10:54 history answered d'alar'cop CC BY-SA 3.0